*

 // A salesman has n things to sale. The cost price of all n things is different out of which p things 

// he is selling on m% profit and n-p things he is going to sell on x% loss. Find his net profit or loss.

#include<stdio.h>

int main()

{

    int n,i,p,m,x,profit=0,loss=0,total;

    

    printf("Enter size of array : ");

    scanf("%d",&n);

    

    int items[n];

    

    printf("\n Enter Price of Each product :");

    

    for( i=0;i<n;i++)

    {

        printf("\nProduct %d of Rs: ",i+1);

        scanf("%d",&items[i]);

    }

    

    printf("\n Enter count of profit products :  ");

    scanf("%d",&p);

    printf("\npercantage of profit : ");

    scanf("%d",&m);

    

    printf("\npercantage of loss : ");

    scanf("%d",&x);

    

    

    for(i=0;i<p;i++)

    {

        profit += (m* items[i])/100;

    }

    

    

    for(i=p;i<n;i++)

    {

        loss += (x* items[i])/100;

    }

    

    

    total = profit - loss;

    

    if(total>0)

    {

        printf("\n Total profit : %d",total);

    }

    else if(total<0){

        printf("\nTotal loss : %d ",total);

    }

    else{

        

        printf("\nNo profit no loss");

    }

    

    return 0;

}